Mercurial > repo
changeset 4179:908d0f920bb1
<kmc> pastelogs 8=+D
author | HackBot |
---|---|
date | Wed, 11 Dec 2013 06:04:23 +0000 |
parents | a4d6f3d2a1df |
children | 703b3cc8110e |
files | paste/paste.29661 |
diffstat | 1 files changed, 31 insertions(+), 0 deletions(-) [+] |
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--- /dev/null Thu Jan 01 00:00:00 1970 +0000 +++ b/paste/paste.29661 Wed Dec 11 06:04:23 2013 +0000 @@ -0,0 +1,31 @@ +2006-12-22.txt:06:02:29: <GreaseMonkey> 8-D = good, 8=D = bad +2007-04-11.txt:04:57:57: <GreaseMonkey> Plof2 8=D +2007-04-11.txt:05:06:35: <GreaseMonkey> don't you know what 8=D is? +2008-02-06.txt:19:51:01: <oklopol> 8===D - - - - O: +2008-02-19.txt:00:50:02: <slereah_> 8===D +2008-03-14.txt:01:49:47: <slereah_> What's the ASCII value for a penis? Is it the value of 8===D? +2008-03-24.txt:18:37:07: <Slereah> It should output this : 8===D +2008-04-29.txt:00:11:47: <Slereah> 8===D (_(__| +2008-05-27.txt:21:27:51: <psygnisfive> for IO, there command to output is 8===D~~ +2008-06-27.txt:12:29:58: <Slereah_> Let 8===D +2008-11-04.txt:20:03:09: <Slereah> 8======D +2009-06-18.txt:08:53:43: <lament> 8===D +2009-06-19.txt:22:23:18: <Slereah_> C===8_o_8===D +2010-06-27.txt:17:50:07: <oklopol> guess what this program does: 8============================D +2010-10-21.txt:21:42:58: <elliott> [[8====D "Surprise!", also represents a penis.]] +2011-01-09.txt:08:09:14: <oklopol> 8=====D (|) +2011-06-11.txt:04:41:12: <zzo38> The table for the header says channel settings for 32 channels, which is 32 bytes long in total, where 255=unused and +128=disabled, so that would agree with my texts, and also agrees with the actual S3M file. +2011-12-11.txt:20:20:21: <warg> also 8=D(0)+8 +2011-12-11.txt:20:20:32: <warg> and 8=D ~ ~ ~ (0)+8 +2012-01-08.txt:09:41:55: <kmc> (>>=) = (8===D) +2012-01-17.txt:08:49:45: <kmc> 8===D +2012-04-14.txt:05:59:19: <kmc> 8====D +2012-04-30.txt:23:03:04: <kmc> parentheses? more like 8=======D +2012-05-08.txt:08:49:19: <kmc> 8===D +2012-05-22.txt:21:32:22: <kmc> 8=d +2012-07-01.txt:23:09:22: <zzo38> 16=C 17=C#=Db 18=D 19=D#=Eb 20=E 21=F 22=F# 23=Gb 24=G 25=G# 26=Ab 27=A 28=A# 29=Bb 30=B 31=B#=Cb 32=C +2012-10-16.txt:21:49:35: <kmc> how about my derivative that uses the symbols 8=D, 8==D, 8===D, 8====D, 8=====D, 8======D, 8=======D, and 8========D +2012-11-17.txt:01:37:10: <kmc> 8=D, 8==D, 8===D, 8====D, 8=====D, 8======D, 8=======D, 8========D +2012-11-22.txt:22:33:00: <kmc> 8=====D +2012-11-22.txt:22:33:40: <kmc> 8=====D +2013-07-16.txt:03:19:10: <kmc> can anyone decrypt this message? 8============================================D