# HG changeset patch
# User HackBot
# Date 1386741863 0
# Node ID 908d0f920bb15536e1a14c019235fe53c60f0011
# Parent  a4d6f3d2a1df70432ff0aadd94659555921b69ba
<kmc> pastelogs 8=+D

diff -r a4d6f3d2a1df -r 908d0f920bb1 paste/paste.29661
--- /dev/null	Thu Jan 01 00:00:00 1970 +0000
+++ b/paste/paste.29661	Wed Dec 11 06:04:23 2013 +0000
@@ -0,0 +1,31 @@
+2006-12-22.txt:06:02:29: <GreaseMonkey> 8-D = good, 8=D = bad
+2007-04-11.txt:04:57:57: <GreaseMonkey> Plof2 8=D
+2007-04-11.txt:05:06:35: <GreaseMonkey> don't you know what 8=D is?
+2008-02-06.txt:19:51:01: <oklopol> 8===D - - - - O:
+2008-02-19.txt:00:50:02: <slereah_> 8===D
+2008-03-14.txt:01:49:47: <slereah_> What's the ASCII value for a penis? Is it the value of 8===D?
+2008-03-24.txt:18:37:07: <Slereah> It should output this : 8===D
+2008-04-29.txt:00:11:47: <Slereah> 8===D (_(__|
+2008-05-27.txt:21:27:51: <psygnisfive> for IO, there command to output is 8===D~~
+2008-06-27.txt:12:29:58: <Slereah_> Let 8===D
+2008-11-04.txt:20:03:09: <Slereah> 8======D
+2009-06-18.txt:08:53:43: <lament> 8===D
+2009-06-19.txt:22:23:18: <Slereah_> C===8_o_8===D
+2010-06-27.txt:17:50:07: <oklopol> guess what this program does: 8============================D
+2010-10-21.txt:21:42:58: <elliott> [[8====D "Surprise!", also represents a penis.]]
+2011-01-09.txt:08:09:14: <oklopol> 8=====D (|)
+2011-06-11.txt:04:41:12: <zzo38> The table for the header says channel settings for 32 channels, which is 32 bytes long in total, where 255=unused and +128=disabled, so that would agree with my texts, and also agrees with the actual S3M file.
+2011-12-11.txt:20:20:21: <warg> also 8=D(0)+8
+2011-12-11.txt:20:20:32: <warg> and 8=D ~ ~ ~ (0)+8
+2012-01-08.txt:09:41:55: <kmc> (>>=) = (8===D)
+2012-01-17.txt:08:49:45: <kmc> 8===D
+2012-04-14.txt:05:59:19: <kmc> 8====D
+2012-04-30.txt:23:03:04: <kmc> parentheses? more like 8=======D
+2012-05-08.txt:08:49:19: <kmc> 8===D
+2012-05-22.txt:21:32:22: <kmc> 8=d
+2012-07-01.txt:23:09:22: <zzo38> 16=C 17=C#=Db 18=D 19=D#=Eb 20=E 21=F 22=F# 23=Gb 24=G 25=G# 26=Ab 27=A 28=A# 29=Bb 30=B 31=B#=Cb 32=C
+2012-10-16.txt:21:49:35: <kmc> how about my derivative that uses the symbols 8=D, 8==D, 8===D, 8====D, 8=====D, 8======D, 8=======D, and 8========D
+2012-11-17.txt:01:37:10: <kmc> 8=D, 8==D, 8===D, 8====D, 8=====D, 8======D, 8=======D, 8========D
+2012-11-22.txt:22:33:00: <kmc> 8=====D
+2012-11-22.txt:22:33:40: <kmc> 8=====D
+2013-07-16.txt:03:19:10: <kmc> can anyone decrypt this message?  8============================================D