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<int-e> learn The password of the month is release incident pilot.
author | HackEso <hackeso@esolangs.org> |
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date | Sun, 03 Nov 2024 00:31:02 +0000 |
parents | 5db7fb79f86d |
children |
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2008-09-02.txt:16:36:21: <AnMaster> 1> [ X || {a, X} <- [{a,1},{b,2},{c,3},{a,4},hello,"wow"]]. 2009-06-05.txt:15:41:48: <AnMaster> 8> [ X || {a, X} <- [{a,1},{b,2},{c,3},{a,4},hello,"foo"]]. 2009-06-25.txt:16:29:47: <ehird> > let primes = [ x | x <- [2..], not (any ((== 0) . (`mod` x)) primes) ] in primes 2009-10-05.txt:20:19:29: <ais523> [ x | x ] is lambda x . x 2010-03-09.txt:12:36:43: <ais523> alise: planned Feather syntax is [ x | f x ] 2010-03-09.txt:15:00:03: <AnMaster> <ais523> alise: planned Feather syntax is [ x | f x ] <-- yay Feather! 2013-02-21.txt:00:01:01: <nooga> i got let d n = [ x | x <- [1..n-1], n `mod` x == 0 ] and let sd n = sum $ d n 2013-02-21.txt:14:04:30: <nooga> http://projecteuler.net/problem=21 my solution: let sd n = sum [ x | x <- [1..n-1], n `mod` x == 0 ] in sum [x | x <- [1..10000], x /= sd x, (sd $ sd x) == x]