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<Zarutian> le/rn Frams\xc3\xb3knarflokkurinn/A, now defunct, political party in Iceland. Like its sister party Sj\xc3\xa1lfst\xc3\xa6\xc3\xb0isflokkurinn it is named by the antonym of what it is. (The name means the Progressive Party but they have nearly always been highly regressive). Think dumb Hill-Billies in ill fitting suits and you get their constiuents.
| author | HackBot |
|---|---|
| date | Sun, 30 Oct 2016 14:33:24 +0000 |
| parents | 5db7fb79f86d |
| children |
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2008-09-02.txt:16:36:21: <AnMaster> 1> [ X || {a, X} <- [{a,1},{b,2},{c,3},{a,4},hello,"wow"]]. 2009-06-05.txt:15:41:48: <AnMaster> 8> [ X || {a, X} <- [{a,1},{b,2},{c,3},{a,4},hello,"foo"]]. 2009-06-25.txt:16:29:47: <ehird> > let primes = [ x | x <- [2..], not (any ((== 0) . (`mod` x)) primes) ] in primes 2009-10-05.txt:20:19:29: <ais523> [ x | x ] is lambda x . x 2010-03-09.txt:12:36:43: <ais523> alise: planned Feather syntax is [ x | f x ] 2010-03-09.txt:15:00:03: <AnMaster> <ais523> alise: planned Feather syntax is [ x | f x ] <-- yay Feather! 2013-02-21.txt:00:01:01: <nooga> i got let d n = [ x | x <- [1..n-1], n `mod` x == 0 ] and let sd n = sum $ d n 2013-02-21.txt:14:04:30: <nooga> http://projecteuler.net/problem=21 my solution: let sd n = sum [ x | x <- [1..n-1], n `mod` x == 0 ] in sum [x | x <- [1..10000], x /= sd x, (sd $ sd x) == x]