view wisdom/anagram @ 12136:d58ddfcf5f07 draft

<fizzie> slwd hackeso//s/almost/&,/;s/quite/&,/;s/unlike/entirely &/
author HackEso <hackeso@esolangs.org>
date Sun, 17 Nov 2019 18:27:51 +0000
parents c31813ca05e8
children
line wrap: on
line source

Interestingly, "Robert Galbraith" is *not* an anagram of "J. K. Rowling".