view 98076 @ 4475:b527947cd0a1

<oerjan> sed -i \'s/Norman/[REDACTED]/g\' quotes
author HackBot
date Wed, 19 Feb 2014 23:48:55 +0000
parents b70362a4c382
children
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-- Hi everyone!
-- Could please someone explain me an output of the function:

splitEvery n list = first : ( splitEvery n rest )
    where (first, rest) = splitAt n list

-- it returns a lis of lists splitEvery :: Int -> [a] -> [[a]]
-- But I don't understand how it works, why it returns list of lists.
-- splitAt returns TUPLE and "first" is somehow joined to it.