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<elliott> addquote <zzo38> Don\'t be too ineffective.
author | HackBot |
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date | Tue, 01 Apr 2014 23:40:58 +0000 |
parents | b70362a4c382 |
children |
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-- Hi everyone! -- Could please someone explain me an output of the function: splitEvery n list = first : ( splitEvery n rest ) where (first, rest) = splitAt n list -- it returns a lis of lists splitEvery :: Int -> [a] -> [[a]] -- But I don't understand how it works, why it returns list of lists. -- splitAt returns TUPLE and "first" is somehow joined to it.