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<oerjan> sed -i \'1183s/ </ </\' quotes
author | HackBot |
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date | Sun, 06 Apr 2014 11:52:53 +0000 |
parents | b70362a4c382 |
children |
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-- Hi everyone! -- Could please someone explain me an output of the function: splitEvery n list = first : ( splitEvery n rest ) where (first, rest) = splitAt n list -- it returns a lis of lists splitEvery :: Int -> [a] -> [[a]] -- But I don't understand how it works, why it returns list of lists. -- splitAt returns TUPLE and "first" is somehow joined to it.