view 98076 @ 4545:29465f76eaa5

<oerjan> sed -i \'1183s/ </ </\' quotes
author HackBot
date Sun, 06 Apr 2014 11:52:53 +0000
parents b70362a4c382
children
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-- Hi everyone!
-- Could please someone explain me an output of the function:

splitEvery n list = first : ( splitEvery n rest )
    where (first, rest) = splitAt n list

-- it returns a lis of lists splitEvery :: Int -> [a] -> [[a]]
-- But I don't understand how it works, why it returns list of lists.
-- splitAt returns TUPLE and "first" is somehow joined to it.